document.write( "Question 573775: One number is 8 more than another. If the sum of the smaller number and twice the larger number is 46, find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #368862 by mathsmiles(68)\"\" \"About 
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Let's use X and Y for the two numbers we're looking for. Let's also assume X is larger than Y. So X is 8 more than Y
\n" ); document.write( "X = Y + 8\r
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\n" ); document.write( "\n" ); document.write( "The next part says to take the sum of the smaller number (Y) and twice the larger number (2X) giving 46.
\n" ); document.write( "Y + 2X = 46\r
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\n" ); document.write( "\n" ); document.write( "That's enough info for us. Let's use substitution since we already have an equation with X by itself. So, substitute (Y+8) for all instances of X in the second equation:
\n" ); document.write( "Y + 2X = 46
\n" ); document.write( "Y + 2(Y+8) = 46 Multiplying out the paren:
\n" ); document.write( "Y + 2Y + 16 = 46 Combining like Y terms:
\n" ); document.write( "3Y + 16 = 46 subtracting 16 from each side:
\n" ); document.write( "3Y = 30 divide by 3 on each side:
\n" ); document.write( "Y = 10
\n" ); document.write( "But what's X? We know X is 8 more than Y from the original problem again.
\n" ); document.write( "If Y is 10, X is 10+8 = 18\r
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\n" ); document.write( "\n" ); document.write( "Checking our answer using the 2nd formula:
\n" ); document.write( "Y + 2X = 46
\n" ); document.write( "(10) + 2(18) = 46
\n" ); document.write( "10 + 36 = 46
\n" ); document.write( "46 = 46 Correct!
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