document.write( "Question 573666: A tank can be filled using hose A alone in 3 hours, using hoses A and B together in 72 minutes, and using hoses A, B and C together in 40 minutes. How many minutes will it take to fill the same tank using only hose C? \n" ); document.write( "
Algebra.Com's Answer #368853 by ankor@dixie-net.com(22740)\"\" \"About 
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A tank can be filled using hose A alone in 3 hours, using hoses A and B together in 72 minutes, and using hoses A, B and C together in 40 minutes.
\n" ); document.write( " How many minutes will it take to fill the same tank using only hose C?
\n" ); document.write( ":
\n" ); document.write( "Find how long for B to fill it alone
\n" ); document.write( "Let a full tank = 1
\n" ); document.write( "Convert 3 hrs to 180 min
\n" ); document.write( ":
\n" ); document.write( "\"72%2F180\" + \"72%2FB\" = 1
\n" ); document.write( "multiply by 180B, results
\n" ); document.write( "72B + 180(72) = 180B
\n" ); document.write( "12960 = 180B - 72B
\n" ); document.write( "12960 = 108B
\n" ); document.write( "B = \"12960%2F108\"
\n" ); document.write( "B = 120 minutes, B alone
\n" ); document.write( ":
\n" ); document.write( "Find C
\n" ); document.write( "\"40%2F180\" + \"40%2F120\" + \"40%2FC\" = 1
\n" ); document.write( "multiply by 360C, results:
\n" ); document.write( "2C(40) + 3C(40) + 360(40) = 360C
\n" ); document.write( "80C + 120C + 14400 = 360C
\n" ); document.write( "14400 = 360C - 200C
\n" ); document.write( "14400 = 160C
\n" ); document.write( "C = \"14400%2F160\"
\n" ); document.write( "C = 90 minutes for C alone
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check that using decimals
\n" ); document.write( "\"40%2F180\" + \"40%2F120\" + \"40%2F90\" =
\n" ); document.write( ".22 + .33 + .44 = .99 ~ 1 a full tank
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