document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=568172>Question 568172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the formula to fund the area of a circle is A = pi r squared, where A equals area and R is the length of the radius of a circle. If the area of a circle is 225 pi square feet find the length of the diameter of the circle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368813 by </B><A HREF=/tutors/aboutme.mpl?userid=mathsmiles><B>mathsmiles(68)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathsmiles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathsmiles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of this circle is 225 pi sq ft.\r<BR>\n" );
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document.write( "The area of the circle is pi R^2.  Therefore<BR>\n" );
document.write( "225 = R^2<BR>\n" );
document.write( "We need to find the square root of 225:<BR>\n" );
document.write( "sqrt (225) = 15 ft\r<BR>\n" );
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document.write( "This tells us the radius.  BUT, going back to the original problem, the question doesn't ask us for radius, it asks for diameter.  Tricky, tricky, tricky  :-)\r<BR>\n" );
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document.write( "The formula relating radius and diameter is:<BR>\n" );
document.write( "D = 2R<BR>\n" );
document.write( "D = 2(15)<BR>\n" );
document.write( "D = 30 ft<BR>\n" );
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