document.write( "Question 573368: 30 gallons of a 20% acid solution is needed for an experiment. Only 40% and 10% acid solution are available. How much of each should be mixed to form the needed solution? \n" ); document.write( "
Algebra.Com's Answer #368797 by ankor@dixie-net.com(22740)\"\" \"About 
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30 gallons of a 20% acid solution is needed for an experiment.
\n" ); document.write( " Only 40% and 10% acid solution are available.
\n" ); document.write( " How much of each should be mixed to form the needed solution?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 40% acid required
\n" ); document.write( "the resulting amt is to be 30 gal, therefore:
\n" ); document.write( "(30-x) = amt of 10% acid required
\n" ); document.write( ":
\n" ); document.write( "A typical mixture equation
\n" ); document.write( ":
\n" ); document.write( ".40x + .10(30-x) = .20(30)
\n" ); document.write( ".40x + 3 - .10x = 6
\n" ); document.write( ".40x - .10x = 6 - 3
\n" ); document.write( ".30x = 3
\n" ); document.write( "x = \"3%2F.3\"
\n" ); document.write( "x = 10 gal of 40% acid
\n" ); document.write( "then
\n" ); document.write( "30 - 10 = 20 gal of the 10% acid \n" ); document.write( "
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