document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=573466>Question 573466</A>: <I><SPAN STYLE=\"word-break: break-all;\">    how do i find the other zeros of f(x) = 2x^3 +11x^2 +9x +2; given that one zero is -1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368783 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do i find the other zeros of f(x) = 2x^3 +11x^2 +9x +2; given that one zero is -1/2<BR>\n" );
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document.write( "Using synthetic division:\r<BR>\n" );
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document.write( "..-1/2..|..2....11....9....2<BR>\n" );
document.write( "................-1...-5...-2<BR>\n" );
document.write( "...........2....10....4....0<BR>\n" );
document.write( "f(x)=(2x+1)(2x^2+10x+4)<BR>\n" );
document.write( "2x^2+10x+4=0<BR>\n" );
document.write( "x^2+5x+2<BR>\n" );
document.write( "By quadratic formula:<BR>\n" );
document.write( "zeros=-4.56 and -0.44<BR>\n" );
document.write( "The 3 zeros of f(x) are -1/2,-4.56 and -0.44<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Note: instead of synthetic division you could have found the zeros by using long division. Divide f(x) by (2x+1) to get the second degree equation. </SPAN>\n" );
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