document.write( "Question 573496: how many cups of 20% alcohol solution and 15% alcohol solution should be mixed in order to make 8 cups of 18% alcohol solution?
\n" ); document.write( "My try:
\n" ); document.write( "x+y=8, (x-x+y=8-x)= y+8-x
\n" ); document.write( "Let x=0.20
\n" ); document.write( "Let y=0.15
\n" ); document.write( "0.20x+0.15y= 0.18(8)
\n" ); document.write( "0.20x+0.15(8-x)=0.18(8)
\n" ); document.write( "0.20x+1.2-0.15x=1.44
\n" ); document.write( "0.35x+1.2=1.44
\n" ); document.write( " -1.2 -1.2
\n" ); document.write( "0.35x=0.24
\n" ); document.write( "x=0.68
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Algebra.Com's Answer #368782 by mananth(16946)\"\" \"About 
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percent ----------------quantity
\n" ); document.write( "Alcohol type I 20.00% ----------------x cups
\n" ); document.write( "Alcohol type II 15.00% ------ 8-x cups
\n" ); document.write( "Mixture 18.00% ---------------- 8
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\n" ); document.write( "20.00%x+15.00%(8-x)= 18.00% * 8
\n" ); document.write( "20x+15( 8-x)=144
\n" ); document.write( "20x+120 -15x=144
\n" ); document.write( "20x-15x=144-120
\n" ); document.write( "5 x = 24
\n" ); document.write( "/ 5
\n" ); document.write( "x= 4.8 cups 20.00% Alcohol type I
\n" ); document.write( " 3.2 cups 15.00% Alcohol type II
\n" ); document.write( "m.ananth@hotmail.ca
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