document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=573352>Question 573352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Christy has a coin collection of nickels and dimes. She has 28 coins worth $2.25. How many of each coin does Christy have?\r<BR>\n" );
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document.write( "I know that .05n + .10D = $2.25<BR>\n" );
document.write( "I also know that n+d=28\r<BR>\n" );
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document.write( "I can figure out these types of problems in my head, but I can't seem to do it using an algebraic equation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368753 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368753\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your equations can be used for substitution or elimination\r<BR>\n" );
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document.write( "n + d = 28 ___ n = 28 - d\r<BR>\n" );
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document.write( "5n + 10d = 225 ___ substituting ___ 5(28 - d) + 10d = 225\r<BR>\n" );
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document.write( "140 - 5d + 10d = 225 ___ 5d = 85\r<BR>\n" );
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document.write( "solve for d, then substitute back to find n </SPAN>\n" );
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