document.write( "Question 573316: The congruent sides of an isosceles triangle measure 6cm, and the base measures 8cm. What is the area? I don't understand how you would find the necessary height of the triangle, or how the base of an isosceles triangle can be longer than the two other congruent sides. Thank you:). \n" ); document.write( "
Algebra.Com's Answer #368729 by stanbon(75887)\"\" \"About 
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The congruent sides of an isosceles triangle measure 6cm, and the base measures 8cm. What is the area? I don't understand how you would find the necessary height of the triangle, or how the base of an isosceles triangle can be longer than the two other congruent sides. Thank you:).
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\n" ); document.write( "Draw the base = 8 cm
\n" ); document.write( "Draw the 2 sides; each = 6 cm
\n" ); document.write( "Draw a perpendicular bisector of the base (that is the height of the triangle).
\n" ); document.write( "Use Pythagoras to find the height
\n" ); document.write( "6^2 = 3^2 + h^2
\n" ); document.write( "36 = 9 + h^2
\n" ); document.write( "h^2 = 27
\n" ); document.write( "h = 3sqrt(3)
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\n" ); document.write( "Area = (1/2) base*height
\n" ); document.write( "Area = (1/2)6*3sqrt(3)
\n" ); document.write( "Area = 9sqrt(3) sq. cm.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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