document.write( "Question 573229: The perimeter of a rectangular fram is 72 inches. The width is 4 more than the length what are the measurements of the width and the length? \n" ); document.write( "
Algebra.Com's Answer #368714 by mathsmiles(68)\"\" \"About 
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The perimeter of a rectangular frame is W + W + L + L. Or 2W + 2L.\r
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\n" ); document.write( "\n" ); document.write( "You were given a couple important pieces of information for this problem.
\n" ); document.write( "First, P = 72 so
\n" ); document.write( "2W + 2L = 72
\n" ); document.write( "And you know the W = L + 4.\r
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\n" ); document.write( "\n" ); document.write( "If we start with the first equation, 2W + 2L = 72 and substitute for W using the 2nd equation, we get:
\n" ); document.write( "2(L+4) + 2L = 72 Multiplying out the paren
\n" ); document.write( "2L + 8 + 2L = 72 Combining terms:
\n" ); document.write( "4L + 8 = 72 Subtracting 8 from each side of the equation:
\n" ); document.write( "4L = 64 dividing each side by 4:
\n" ); document.write( "L = 16\r
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\n" ); document.write( "\n" ); document.write( "If the width is 4 more than the length, then
\n" ); document.write( "W = 16 + 4 = 20\r
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\n" ); document.write( "\n" ); document.write( "Checking:
\n" ); document.write( "2(16) + 2(20) = 72
\n" ); document.write( "32 + 40 = 72
\n" ); document.write( "72 = 72 Correct!\r
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