document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54612>Question 54612</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help w/ the following exponential function:<BR>\n" );
document.write( "The number of bacteria present in a culture after t minutes is given as B=100^ kt.  if there are 6231 bacteria present after 11 minutes, find k.<BR>\n" );
document.write( "Thank you, Aimee </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36868 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number of bacteria present in a culture after t minutes is given as B=100^ kt. if there are 6231 bacteria present after 11 minutes, find k.<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "6231=100^(11k)<BR>\n" );
document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "log6231 = (11k)log100<BR>\n" );
document.write( "3.79456=22k<BR>\n" );
document.write( "k=0.1725<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );