document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=573047>Question 573047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sides of a square are lengthened by 6cm the area becomes 100cm^2. Find the length of a side of the original square.\r<BR>\n" );
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document.write( "The length of a side of the original square is _____ cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368646 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the sides of a square are lengthened by 6cm the area becomes 100cm^2. Find the length of a side of the original square.<BR>\n" );
document.write( "(x+6)(x+6) = 100<BR>\n" );
document.write( "FOIL<BR>\n" );
document.write( "x^2 + 6x + 6x + 36 - 100 = 0<BR>\n" );
document.write( "x^2 + 12x - 64 = 0<BR>\n" );
document.write( "Factors to<BR>\n" );
document.write( "(x+16)(x-4) = 0<BR>\n" );
document.write( "The positive solution<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check: (4+6) * (4+6) = 100<BR>\n" );
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document.write( "The length of a side of the original square is 4 cm. </SPAN>\n" );
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