document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54614>Question 54614</A>: <I><SPAN STYLE=\"word-break: break-all;\">   Please help w/ the following.  Thank You.\r<BR>\n" );
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document.write( "   If 10,000 is invested at 9% compounded monthly for 6 years the compounded amount is given by A=10,000(1.0075)^72.  Given that log 1.0075=0.00325, find log A. (Note that 10,000=10^4). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36864 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36864\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 10,000 is invested at 9% compounded monthly for 6 years the compounded amount is given by A=10,000(1.0075)^72. Given that log 1.0075=0.00325, find log A. <BR>\n" );
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document.write( "log A = log 10000 + 72(log 1.0075)<BR>\n" );
document.write( "log A = 4 +72(0.00325)<BR>\n" );
document.write( "log A = 4 + 0.234<BR>\n" );
document.write( "log A = 4.234<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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