document.write( "Question 572396: simplify (solve if possible).\r
\n" ); document.write( "\n" ); document.write( " (x-2) (x)
\n" ); document.write( " -------- + --------
\n" ); document.write( " (x^2+x-12) (x^2-2x-3)\r
\n" ); document.write( "\n" ); document.write( "the x-2 is over the x^2+x-12
\n" ); document.write( "the symbol is a \"+\" for addition
\n" ); document.write( "the x is over the x^2-2x-3
\n" ); document.write( "thank you!
\n" ); document.write( "

Algebra.Com's Answer #368627 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
(x-2)/(x^2+x-12)+x/(x^2-2x-3)=\"%28x-2%29%2F%28x%5E2%2Bx-12%29%2Bx%2F%28x%5E2-2x-3%29\"=
\n" ); document.write( "I would factor denominators first and see what I can use for a common denominator.
\n" ); document.write( "\"%28x-2%29%2F%28x%5E2%2Bx-12%29%2Bx%2F%28x%5E2-2x-3%29\"=\"%28x-2%29%2F%28%28x%2B4%29%28x-3%29%29%2Bx%2F%28%28x-3%29%28x%2B1%29%29\" =
\n" ); document.write( "Then I would work on the numerator parts leaving the denominators alone (and hoping to be able to simplify the result).
\n" ); document.write( " = = \"%282x%5E2%2B3x-2%29%2F%28%28x%2B4%29%28x-3%29%28x%2B1%29%29\"
\n" ); document.write( "We can factor the numerator
\n" ); document.write( "\"%282x%5E2%2B3x-2%29%2F%28%28x%2B4%29%28x-3%29%28x%2B1%29%29\" = \"%282x-1%29%28x%2B2%29%2F%28%28x%2B4%29%28x-3%29%28x%2B1%29%29\"
\n" ); document.write( "Nothing cancels out, so I'll call it fully simplified.
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