document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=572988>Question 572988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We can't seem to understand the method for putting together the equation on a Mixture Word Problem.  The MATH is no problem; only the organization of the equation itself:\r<BR>\n" );
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document.write( "Two kinds of coffee were blended together, one worth $6.50 a pound and the other worth $5.95 a pound.  The blend contained ten pounds more than twice as much as the $5.95 coffee than of the $6.50 coffee. How much of each kind was used if the value of the blend is $280.30? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368618 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two kinds of coffee were blended together, one worth $6.50 a pound and the other worth $5.95 a pound. The blend contained ten pounds more than twice as much as the $5.95 coffee than of the $6.50 coffee. How much of each kind was used if the value of the blend is $280.30?<BR>\n" );
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document.write( "Let x = amount (lbs) of $5.95 coffee<BR>\n" );
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document.write( "2x+10 = amount (lbs) of $6.50 coffee<BR>\n" );
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document.write( "5.95x + 6.50(2x+10) =  280.30<BR>\n" );
document.write( "5.95x + 13x+65 =  280.30<BR>\n" );
document.write( "18.95x+65 =  280.30<BR>\n" );
document.write( "18.95x =  215.3<BR>\n" );
document.write( "x = 11.36 lbs ($5.95 coffee)<BR>\n" );
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document.write( "$6.50 coffee:<BR>\n" );
document.write( "2x+10 = 2(11.36)+10 = 32.72 lbs </SPAN>\n" );
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