document.write( "Question 572980: how many liters of a 80% acid solution must be mixed with a 10% acid solution to get 560liters of a 70% acid solution \n" ); document.write( "
Algebra.Com's Answer #368617 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Acid solution Type I 80.00% ---------------- x L
\n" ); document.write( "Acid solution type II 10.00% ------ 560 - x L
\n" ); document.write( "Mixture 70.00% ---------------- 560
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\n" ); document.write( "80.00%x+10.00%(560-x)=70.00%*560
\n" ); document.write( "80x+10(560-x)= 39200
\n" ); document.write( "80x+5600-10x=39200
\n" ); document.write( "80x-10x =39200 -5600
\n" ); document.write( "70x= 33600
\n" ); document.write( "/70
\n" ); document.write( "x =480L 80.00% Acid solution Type I
\n" ); document.write( "80L 10.00% Acid solution type II
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