document.write( "Question 572980: how many liters of a 80% acid solution must be mixed with a 10% acid solution to get 560liters of a 70% acid solution \n" ); document.write( "
Algebra.Com's Answer #368617 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Acid solution Type I 80.00% ---------------- x L \n" ); document.write( "Acid solution type II 10.00% ------ 560 - x L \n" ); document.write( "Mixture 70.00% ---------------- 560 \n" ); document.write( " \n" ); document.write( "80.00%x+10.00%(560-x)=70.00%*560 \n" ); document.write( "80x+10(560-x)= 39200 \n" ); document.write( "80x+5600-10x=39200 \n" ); document.write( "80x-10x =39200 -5600 \n" ); document.write( "70x= 33600 \n" ); document.write( "/70 \n" ); document.write( "x =480L 80.00% Acid solution Type I \n" ); document.write( "80L 10.00% Acid solution type II \n" ); document.write( " \n" ); document.write( " |