document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=572454>Question 572454</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x-8y=7<BR>\n" );
document.write( "5x+4y=5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368600 by </B><A HREF=/tutors/aboutme.mpl?userid=mathsmiles><B>mathsmiles(68)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathsmiles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathsmiles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You don't specify what method to use to solve this equation, so lucky me!  I get to pick!!!  :-)\r<BR>\n" );
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document.write( "These don't lend themselves to substitution, so I'm going to use the other method.  (Elimination?)\r<BR>\n" );
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document.write( "2x - 8y = 7<BR>\n" );
document.write( "5x + 4y = 5\r<BR>\n" );
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document.write( "I'm going to try to eliminate the y term in both of these.  To do that, I need the same factor on the y term, so ... \r<BR>\n" );
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document.write( "2x - 8y = 7  (unchanged from above)<BR>\n" );
document.write( "2(5x + 4y) = 2(5)   multiply both sides by 2 giving ... <BR>\n" );
document.write( "10x + 8y = 10\r<BR>\n" );
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document.write( "Now let me rewrite the equations using this adjusted 2nd equation:<BR>\n" );
document.write( "2x  - 8y = 7<BR>\n" );
document.write( "10x + 8y = 10  Add these together and ... <BR>\n" );
document.write( "12x      = 17<BR>\n" );
document.write( "Divide both sides by 12 (yucky)<BR>\n" );
document.write( "x = 17/12  (Are you sure you copied this down correctly?)\r<BR>\n" );
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document.write( "2(17/12) - 8y = 7<BR>\n" );
document.write( "17/6 - 8y = 7<BR>\n" );
document.write( "Add 8y to both sides:<BR>\n" );
document.write( "17/6 = 7 + 8y<BR>\n" );
document.write( "Multiply both sides by 6<BR>\n" );
document.write( "17 = 6(7+8y)<BR>\n" );
document.write( "17 = 42 + 48y<BR>\n" );
document.write( "Subtract 42 from both sides:<BR>\n" );
document.write( "-25 = 48y<BR>\n" );
document.write( "Divide both sides by 48<BR>\n" );
document.write( "-25/48 = y    (yucky yucky yucky - my very technical term)\r<BR>\n" );
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document.write( "Checking:<BR>\n" );
document.write( "1st equation:<BR>\n" );
document.write( "2(17/12) -8(-25/48) = 7<BR>\n" );
document.write( "Factoring out a 2 from numerator and denominator of first term:<BR>\n" );
document.write( "17/6 - 8(-25/48) = 7 now getting rid of the double negative in the 2nd term:<BR>\n" );
document.write( "17/6 + 8(25/48) = 7  <BR>\n" );
document.write( "Factoring out an 8 from the numerator and denominator of 2nd term:<BR>\n" );
document.write( "17/6 + 25/6 = 7<BR>\n" );
document.write( "42/6 = 7<BR>\n" );
document.write( "7 = 7 Correct!\r<BR>\n" );
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document.write( "2nd equation:<BR>\n" );
document.write( "5(17/12) + 4(-25/48) = 5  We can factor a 4 from numberator and denominator in 2nd term:<BR>\n" );
document.write( "5(17/12) + (-25/12) = 5<BR>\n" );
document.write( "85/12 - 25/12 = 5<BR>\n" );
document.write( "60/12 = 5<BR>\n" );
document.write( "5 = 5 Correct!\r<BR>\n" );
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document.write( "Whew! That was ugly, but it worked out in the end.  Hope you were able to follow.  These messy ones can be confusing if we're not doing them together.<BR>\n" );
document.write( "Good luck!!  Come back for more some time.  :-)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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