document.write( "Question 572423: Find a point-slope equation for the line tangent to the circle at (4,9), whose center is (2,0) \n" ); document.write( "
Algebra.Com's Answer #368598 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! The slope of the radius connecting those two points is\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the line tangent to the circle is perpendicular to this radius, the slope of the tangent line will be -1/m, or -2/9. We know that (4,9) is on the desired line so we can write in point-slope form:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |