document.write( "Question 572584: I cannot get this please help
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document.write( "solve using the substitution method
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document.write( "4m+n=27
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document.write( "m-3n=23 \n" );
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Algebra.Com's Answer #368597 by mathsmiles(68)![]() ![]() You can put this solution on YOUR website! (I think you're the same person I just helped with another substitution.)\r \n" ); document.write( "\n" ); document.write( "What we want is to get one of the variables alone on one side of the equation. Looking at the two equations, my choice is getting M by itself in the 2nd equation.\r \n" ); document.write( "\n" ); document.write( "m-3n=23 \n" ); document.write( "Add 3n to both sides and wallah! \n" ); document.write( "+3n +3n \n" ); document.write( "m = 23 + 3n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, \"substitute\" this for m in the first equation (aha you say!) \n" ); document.write( "4m + n = 27 \n" ); document.write( "4(23+3n) + n = 27 \n" ); document.write( "92 + 12n + n = 27 \n" ); document.write( "92 + 13n = 27 \n" ); document.write( "subtract 92 from both sides: \n" ); document.write( "-92 -92 \n" ); document.write( "13n = -65 \n" ); document.write( "Divide both sides by 13: \n" ); document.write( "n = -5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "SOOOO, \n" ); document.write( "m = 23 + 3n \n" ); document.write( "m = 23 + 3(-5) \n" ); document.write( "m = 23 - 15 \n" ); document.write( "m = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking: \n" ); document.write( "4(8) + -5 = 27 \n" ); document.write( "32 - 5 = 27 \n" ); document.write( "27 = 27 Correct \n" ); document.write( "8-3(-5) = 23 \n" ); document.write( "8 + 15 = 23 \n" ); document.write( "23 = 23 Correct!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I wish I had your textbook to look up elimination method and I could help you with that. It's not the term I used and I'm afraid I'll misguide you. If you could look that up and add it to one of your \"elimination\" method questions, I'll stay online a little longer. \r \n" ); document.write( "\n" ); document.write( "Smile! You're going to get this! You now know \"substitution\". :-) \n" ); document.write( " |