document.write( "Question 572915: a newspaper carrier has $4.25 in change. He has seven more quarters than dimes but four times as many nickels as quarters. How many coins of each type does he have? \n" ); document.write( "
Algebra.Com's Answer #368571 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let dimes be x \n" ); document.write( "quarters = x+7 \n" ); document.write( "nickels = 4(x+7)\r \n" ); document.write( "\n" ); document.write( "the value = $4.25 = 425cents\r \n" ); document.write( "\n" ); document.write( "value equation \n" ); document.write( "10x+25(x+7)+5*4(x+7)=425\r \n" ); document.write( "\n" ); document.write( "10x+25x+175+20x+140=425\r \n" ); document.write( "\n" ); document.write( "55x+315=425 \n" ); document.write( "55x= 425-315\r \n" ); document.write( "\n" ); document.write( "55x=110 \n" ); document.write( "x= 2 \n" ); document.write( "2 dimes \n" ); document.write( "quarters =(2+7)=9 \n" ); document.write( "nickels = 4(x+7)=4*9=36 \n" ); document.write( "CHECK\r \n" ); document.write( "\n" ); document.write( "36*5 + 9*25+2*10= \n" ); document.write( "180+225+20=425 \n" ); document.write( " |