document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=572221>Question 572221</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 15. one number is 4 times the other.<BR>\n" );
document.write( " what are the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368570 by </B><A HREF=/tutors/aboutme.mpl?userid=mathsmiles><B>mathsmiles(68)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathsmiles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathsmiles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368570\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's use X and Y to denote the two numbers we're looking for.\r<BR>\n" );
document.write( "\n" );
document.write( "X + Y = 15<BR>\n" );
document.write( "X = 4Y\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Substitute the 4Y into the first equation for X gives us<BR>\n" );
document.write( "(4Y) + Y = 15<BR>\n" );
document.write( "5Y = 15  Divide both sides by 5<BR>\n" );
document.write( "Y = 3.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "One number is 3.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "But we know 3 and the other number add to 15.  Therefore,<BR>\n" );
document.write( "X + 3 = 15<BR>\n" );
document.write( "X = 12\r<BR>\n" );
document.write( "\n" );
document.write( "So the two numbers are 3 and 12.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Check:<BR>\n" );
document.write( "3 + 12 = 15<BR>\n" );
document.write( "AND<BR>\n" );
document.write( "4 X 3 = 12  Correct! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );