document.write( "Question 572524: Tom, dick, and harry paint houses. If all three work together, they finish in five days. If tom and dick work together they finish in eight days. If tom and harry work together they finish in ten days. How long would it take each one alone to paint a house? \n" ); document.write( "
Algebra.Com's Answer #368562 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Tom, dick, and harry paint houses. \n" ); document.write( " If all three work together, they finish in five days. \n" ); document.write( " If tom and dick work together they finish in eight days. \n" ); document.write( " If tom and harry work together they finish in ten days. \n" ); document.write( "How long would it take each one alone to paint a house? \n" ); document.write( ": \n" ); document.write( "Let t = Tom's time to paint the house alone \n" ); document.write( "Let d = Dick's time \n" ); document.write( "Let h = Harry's time \n" ); document.write( "Let the competed job = 1 \n" ); document.write( ": \n" ); document.write( "Write a shared work equation for each scenario \n" ); document.write( ": \n" ); document.write( "\"Tom, dick, and harry paint houses. If all three work together, they finish in five days.\" \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( "\" If tom and dick work together they finish in eight days.\" \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "\"If tom and harry work together they finish in ten days.\" \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "We can use elimination here, mult the 1st eq by 2, subtract the 3rd eq \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-------------------------------------------subtraction eliminates t and h \n" ); document.write( "10/d = 1 \n" ); document.write( "multiply both sides by d \n" ); document.write( "d = 10 days for Dick to do the job alone \n" ); document.write( ": \n" ); document.write( "Use the 2nd equation to find t \n" ); document.write( " \n" ); document.write( "multiply by 10t, results: \n" ); document.write( "10(8) + t(8) = 10t \n" ); document.write( "80 = 10t - 8t \n" ); document.write( "80 = 2t \n" ); document.write( "t = 40 days for Tom to do the job alone \n" ); document.write( ": \n" ); document.write( "Use the 3rd equation to find h \n" ); document.write( " \n" ); document.write( "multiply by 40h \n" ); document.write( "10h + 40(10) = 40h \n" ); document.write( "400 = 40h - 10h \n" ); document.write( "400 = 30h \n" ); document.write( "h = 400/30 \n" ); document.write( "h = 13 \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Let's see if this checks out using decimals in the 1st equation \n" ); document.write( " \n" ); document.write( ".125 + .50 + .375 = 1; confirms our solutions of: \n" ); document.write( ": \n" ); document.write( "Tom takes 40 days, rather useless \n" ); document.write( "Dick takes 10 days, carrying the load \n" ); document.write( "Harry takes 13 1/3 days, a good helper\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |