document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=572899>Question 572899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The cost of driving your vehicle can be calculated using the following equation:<BR>\n" );
document.write( "Fuel cost for one year = (miles driven * price per gallon) ÷  (fuel effieciency rate).  If you drove 22,500 miles, paid $225 per gallon of gasoline, and spent a total of $2025 on gasoline, what is the fuel effieciency rate of your car? How much would you have saved if your cars's fuel efficiency rate were 35 miles per gallon?<BR>\n" );
document.write( "My grade is depending on these questions and I am very lost, please help me if you can.  I would greatly appreciate it. <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368561 by </B><A HREF=/tutors/aboutme.mpl?userid=mathsmiles><B>mathsmiles(68)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathsmiles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathsmiles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Fuel cost for one year = $2025<BR>\n" );
document.write( "Price per gallon = $225<BR>\n" );
document.write( "Miles driven = 22,500\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Fuel cost for one year = (miles driven * price per gallon) / (fuel efficiency rate)\r<BR>\n" );
document.write( "\n" );
document.write( "You have everything but the fuel efficiency rate already.  Just need to solve for that.  Let's call that E\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So, substituting,<BR>\n" );
document.write( "2025 = (22500 * 2.25) / E.\r<BR>\n" );
document.write( "\n" );
document.write( "2025 = (50625) / E<BR>\n" );
document.write( "To get E in the numerator, we need to multiply each side by E.\r<BR>\n" );
document.write( "\n" );
document.write( "2025 * E = 50625<BR>\n" );
document.write( "Now divide both sides by 2025 to get E alone.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "E = 25.  Fuel efficiency is 25.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The second part of the question gives you a new E, but wants us to calculate the new fuel cost for one year.  So back to the formula:<BR>\n" );
document.write( "Fuel cost for one year = (miles driven * price per gallon) / (fuel efficiency rate)<BR>\n" );
document.write( "Let C = cost for one year<BR>\n" );
document.write( "C = (22500 * 2.25) / 35<BR>\n" );
document.write( "C = 1446.43<BR>\n" );
document.write( "If the fuel efficiency were 35, the cost per year would have been $1446.43.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The savings would have been:  $2025 - $1446.43 = $578.57\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );