document.write( "Question 572842: solve the equation for y\r
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document.write( "(5/y-3)+ (10/y^2-y-6) = (y/y+2)]\r
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document.write( "(five over y-3) plus (10 over y squared minus y minus 6) equals (y over y+2)\r
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document.write( "1.Im not sure if i did it right, i found the least common denominator which is (y-3)(y+2) and multiplied to the missing part of the least common denominator to the top to get:\r
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document.write( "5(y+2)/(y-3)(y+2) - 10/(y-3)(y+2) = y(y-3)/(y+2)(y-3)\r
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document.write( "2.Then i combined like terms and simplified to get\r
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document.write( "5y+20/(y-3)(y+2) = (y^2)-3y/(y+2)(y-3)\r
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document.write( "3. My final answer was
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document.write( "5y(y+4)/ (y+2)(y-3)\r
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document.write( "Is it correct?\r
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Algebra.Com's Answer #368522 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply by (y-3)(y+2)\r \n" ); document.write( "\n" ); document.write( "5(y+2) +10 =y(y-3)\r \n" ); document.write( "\n" ); document.write( "5y+10+10=y^2-3y\r \n" ); document.write( "\n" ); document.write( "5y+20=y^2-3y\r \n" ); document.write( "\n" ); document.write( "y^2-8y-20=0\r \n" ); document.write( "\n" ); document.write( "y^2-10y+2y-20=0 \n" ); document.write( "y(y-10)+2(y-10)=0 \n" ); document.write( "(y-10)(y+2)=0 \n" ); document.write( "y=10 OR -2 \n" ); document.write( " |