document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=572842>Question 572842</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the equation for y\r<BR>\n" );
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document.write( "(5/y-3)+ (10/y^2-y-6) = (y/y+2)]\r<BR>\n" );
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document.write( "(five over y-3) plus (10 over y squared minus y minus 6) equals (y over y+2)\r<BR>\n" );
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document.write( "1.Im not sure if i did it right, i found the least common denominator which is (y-3)(y+2) and multiplied to the missing part of the least common denominator to the top to get:\r<BR>\n" );
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document.write( "5(y+2)/(y-3)(y+2)    -    10/(y-3)(y+2)    =  y(y-3)/(y+2)(y-3)\r<BR>\n" );
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document.write( "2.Then i combined like terms and simplified to get\r<BR>\n" );
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document.write( "5y+20/(y-3)(y+2) = (y^2)-3y/(y+2)(y-3)\r<BR>\n" );
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document.write( "3. My final answer was <BR>\n" );
document.write( "5y(y+4)/ (y+2)(y-3)\r<BR>\n" );
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document.write( "Is it correct?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368520 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "You were correct up to this point:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{5(y\ +\ 2)\ -\ 10}{(y\ -\ 3)(y\ +\ 2)}\ =\ \frac{y^2\ -\ 3y}{(y\ -\ 3)(y\ +\ 2)}\">\r<BR>\n" );
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document.write( "But <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE 5(y\ +\ 2)\ -\ 10\ =\ 5y\ +\ 10\ -\ 10\ =\ 5y\ \neq\ 5y\ +\ 20\">, so the next step looks like:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{5y}{(y\ -\ 3)(y\ +\ 2)}\ =\ \frac{y^2\ -\ 3y}{(y\ -\ 3)(y\ +\ 2)}\">\r<BR>\n" );
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document.write( "Then multiply both sides by the denominator to eliminate the denominator leaving you with:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 5y\ =\ y^2\ -\ 3y\">\r<BR>\n" );
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document.write( "Which becomes\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ y^2\ -\ 8y\ =\ 0\">\r<BR>\n" );
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document.write( "hence\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 0\">\r<BR>\n" );
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document.write( "or\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 8\">\r<BR>\n" );
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document.write( "Check to be certain that neither root will drive any original denominator to zero before declaring either an element of the solution set.  You might want to check the work by substituting back into the original equation.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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