document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=572638>Question 572638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the same amount of time a new production assembly robot can assemble 8 times as many<BR>\n" );
document.write( "transmissions as an old assembly line. If the new robot can assemble 'x' transmissions per hour, how<BR>\n" );
document.write( "many transmissions can the new robot and the old assembly line produce together in five days of round<BR>\n" );
document.write( "the clock production.<BR>\n" );
document.write( "for this i started with both robots 1 hr work = x+ x/8 = 9x / 8 ....after this i have no idea ...can anyone help me....? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368467 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368467\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> new ___ x per hr , so 24x per day\r<BR>\n" );
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document.write( "old ___ 1/8 of new , so 3x per day\r<BR>\n" );
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document.write( "together ___ 27x per day </SPAN>\n" );
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