document.write( "Question 572586: solve by substitution method
\n" ); document.write( "5x+2y=-7
\n" ); document.write( "7x+3y=13
\n" ); document.write( "I am having an extremly hard time figuring this out PLEASE help
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Algebra.Com's Answer #368454 by Alan3354(69443)\"\" \"About 
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solve by substitution method
\n" ); document.write( "5x+2y=-7
\n" ); document.write( "7x+3y=13
\n" ); document.write( "----------
\n" ); document.write( "The usual approach is to solve for either x or y in 1 of the eqns.
\n" ); document.write( "----
\n" ); document.write( "5x+2y=-7
\n" ); document.write( "2y = -5x - 7
\n" ); document.write( "y = -5x/2 - 7/2
\n" ); document.write( "----
\n" ); document.write( "Sub for y in the other eqn
\n" ); document.write( "7x+3y=13
\n" ); document.write( "7x + 3(-5x/2 - 7/2) = 13
\n" ); document.write( "7x - 15x/2 - 21/2 = 13
\n" ); document.write( "-x/2 = 47/2
\n" ); document.write( "x = -47
\n" ); document.write( "-------
\n" ); document.write( "y = -5x/2 - 7/2
\n" ); document.write( "y = 235/2 - 7/2
\n" ); document.write( "y = 114
\n" ); document.write( "======================
\n" ); document.write( "A different method:
\n" ); document.write( "5x+2y=-7
\n" ); document.write( "7x+3y=13
\n" ); document.write( "----
\n" ); document.write( "15x + 6y = -21
\n" ); document.write( "14x + 6y = 26
\n" ); document.write( "Solve for 6y, then sub. You avoid fractions that way.
\n" ); document.write( "15x + 6y = -21
\n" ); document.write( "--> 6y = -15x - 21
\n" ); document.write( "--------------
\n" ); document.write( "21x + 6y = 39
\n" ); document.write( "14x + (-15x - 21) = 26
\n" ); document.write( "etc, same answer
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