document.write( "Question 572513: I need help with the following problem:\r
\n" ); document.write( "\n" ); document.write( "Solve by the subsitution method.\r
\n" ); document.write( "\n" ); document.write( "9x + 2y = -37
\n" ); document.write( "-3x + y = 19
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Algebra.Com's Answer #368443 by mananth(16946)\"\" \"About 
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-3 x + 1 y = 19 .............1
\n" ); document.write( "1 y = 19 3 x ---------2
\n" ); document.write( "/ 1 =
\n" ); document.write( " y = 19 3 x
\n" ); document.write( "Substitute y in (2)
\n" ); document.write( "9 x + 2 ( 19 3 x ) =
\n" ); document.write( "9 x + 38 + 6 x = -37
\n" ); document.write( "9 x 6 x = -75
\n" ); document.write( "15 x = -75
\n" ); document.write( "/ 15
\n" ); document.write( "x= -5
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "9 x + 2 y = -37
\n" ); document.write( "9 * -5 + 2 y = -37
\n" ); document.write( "-45 + 2 y = -37
\n" ); document.write( "2 y = 8
\n" ); document.write( "/ 2
\n" ); document.write( "y= 4
\n" ); document.write( "m.ananth@hotmail.ca
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