document.write( "Question 572522: solve the following system by graphing and algebraically.
\n" ); document.write( "y=1-x^2
\n" ); document.write( "4x^2+y^2=16
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Algebra.Com's Answer #368432 by KMST(5328)\"\" \"About 
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ALGEBRAICALLY
\n" ); document.write( "\"y=1-x%5E2\" --> \"x%5E2=1-y\"
\n" ); document.write( "Substituting into \"4x%5E2%2By%5E2=16\",
\n" ); document.write( "\"4%281-y%29%2By%5E2=16\" --> \"4-4y%2By%5E2=16\" --> \"y%5E2-4y-12=0\"
\n" ); document.write( "The solutions to the above equation can be found by factoring
\n" ); document.write( "\"y%5E2-4y-12=0\" --> \"%28y-6%29%28y%2B2%29=0\" --> \"y=6\" or \"y=-2\"
\n" ); document.write( "\"y=6\" does not yield a real solution for x in \"x%5E2=1-y\"
\n" ); document.write( "\"y=-2\" results in \"x%5E2=1-%28-2%29\" --> \"x%5E2=3\" and \"x=sqrt%283%29\" or \"x=-sqrt%283%29\"
\n" ); document.write( "The solutions are (\"-sqrt%283%29\",-2) and (\"sqrt%283%29\",-2).
\n" ); document.write( "GRAPHICALLY
\n" ); document.write( "I do not know if use of a graphing calculator is expected, but without it we could sketch, and then calculate to see if what looks like the intersection of the graphs really adds up.
\n" ); document.write( "\"y=1-x%5E2\" graphs as a parabola with maximum at (0,1) and x-intercepts at x=-1 and x=1.
\n" ); document.write( "\"4x%5E2%2By%5E2=16\" dividing both sides by 16 turns into \"x%5E2%2F4%2By%5E2%2F16=1\".
\n" ); document.write( "That's the standard form of an ellipse centered at the origin, y intercepts (vertices) at y=-4 and y=4, and x-intercepts at x=-2 and x=2.
\n" ); document.write( "That would make us expect that the curves cross at negative values of y, with x between -2 and 2.
\n" ); document.write( "The graphs would look like this
\n" ); document.write( " If the graph suggested to you that the curves cross about at about y=-2, calculations would show you that y=-2 gives the same x value for both equations and you would have the solution.
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