document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=572516>Question 572516</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am building a Triangular chicken coop.<BR>\n" );
document.write( "A=4ft(tall)<BR>\n" );
document.write( "B=4ft(wide)<BR>\n" );
document.write( "D=5.66ft(hypotnuse)<BR>\n" );
document.write( "of A the lower 2.5ft is going to be open while the remaining 1.5 ft will be enclosed making the lower \"half\" a right trapizoid and the top a right triangle <BR>\n" );
document.write( "so if the trapizoid is <BR>\n" );
document.write( "a=2.5ft tall <BR>\n" );
document.write( "B=4ft wide<BR>\n" );
document.write( "c=? (also width of upper right triangle)<BR>\n" );
document.write( "d=? (hypotnuse)\r<BR>\n" );
document.write( "\n" );
document.write( "1.5ft of A c and the remaining difference of D = the enclosed area<BR>\n" );
document.write( "i just need to know what c & d are of the trapaziod that is the simpilest way i can put the question im doing this on my own and i have been out of school for just a year but im just stuck and dont remember how to do it i would very much appreciate your help Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368430 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368430\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if i understand your question correctly, you are looking for the dimensions of the trapezoid, the upper half of which will be the base of the triangle on top.<BR>\n" );
document.write( "the best way to show you what i mean is by the diagram below.<BR>\n" );
document.write( "it has the measurements you are looking for i believe.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2012/feb141.jpg\" alt = \"$$$\" /><BR>\n" );
document.write( "ABC is your original triangle.<BR>\n" );
document.write( "ADE is the top part of the coop.<BR>\n" );
document.write( "DECB is the bottom part of the coop.<BR>\n" );
document.write( "DE is parallel to BC so it forms triangle ADE similar to ABC because all the corresponding angles are equal.<BR>\n" );
document.write( "if the triangles are similar, then their corresponding sides are proportional.<BR>\n" );
document.write( "i drew EF parallel to DB to show you that all 3 triangles are similar.<BR>\n" );
document.write( "those triangle are:<BR>\n" );
document.write( "ADE, ABC, and EFC<BR>\n" );
document.write( "your coop can be constructed with or without EF as a brace.<BR>\n" );
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