document.write( "Question 572498: How many liters of a 30% alcohol solution must be mixed with 20 liters of a 70% solution to get a 40% solution? \n" ); document.write( "

Algebra.Com's Answer #368427 by Maths68(1474) $\"\"$ $\"About$

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Solution A
\n" ); document.write( "Amount = x
\n" ); document.write( "Concentration =30% =0.3\r
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\n" ); document.write( "\n" ); document.write( "Solution B
\n" ); document.write( "Amount = 20
\n" ); document.write( "Concentration =70% = 0.7\r
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\n" ); document.write( "\n" ); document.write( "Resultant Solution
\n" ); document.write( "Amount =20+x
\n" ); document.write( "Concentration =40%=0.4\r
\n" ); document.write( "\n" ); document.write( "[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = Amount of Resultant * Concentration of resultant\r
\n" ); document.write( "\n" ); document.write( "(x)(0.3)+(20)(0.7)= (20+x)(0.4)
\n" ); document.write( "0.3x+14=8+0.4x
\n" ); document.write( "0.3x-0.4x=8-14
\n" ); document.write( "-0.1x=-6
\n" ); document.write( "-0.1x/-0.1=-6/-0.1
\n" ); document.write( "x=60\r
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\n" ); document.write( "\n" ); document.write( "Solution A
\n" ); document.write( "Amount = x = 60 liters
\n" ); document.write( "Concentration =30% =0.3\r
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\n" ); document.write( "\n" ); document.write( "60 liters of a 30% alcohol solution must be mixed with 20 liters of a 70% solution to get a 40% solution? \n" ); document.write( "

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