document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=572476>Question 572476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much pure acid must be added to 6 gallons of 4% acid solution to make 20% acid solution?\r<BR>\n" );
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document.write( "So far I have let x +6 *.04 ?? not sure if this correct  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368408 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much pure acid must be added to 6 gallons of 4% acid solution to make 20% acid solution? <BR>\n" );
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document.write( "Let x = amount (gallons) of pure acid added<BR>\n" );
document.write( "then<BR>\n" );
document.write( "\"pure acid\" + \"acid in 4% solution\" = 20% of total mixture<BR>\n" );
document.write( "x + .04(6) = .20(6+x)<BR>\n" );
document.write( "x + .24 = 1.2+.20x<BR>\n" );
document.write( ".80x + .24 = 1.2<BR>\n" );
document.write( ".80x = 0.96<BR>\n" );
document.write( "x = 1.2 gallons<BR>\n" );
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