document.write( "Question 572361: 2= 4/n + 1/3 \n" ); document.write( "
Algebra.Com's Answer #368382 by rfer(16322)\"\" \"About 
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2-1/3=4/n
\n" ); document.write( "5/3=4/n
\n" ); document.write( "5/3n=4
\n" ); document.write( "n=4/(5/3)
\n" ); document.write( "n=4*3/5
\n" ); document.write( "n=12/5
\n" ); document.write( "n=2 2/5
\n" ); document.write( "
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