document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=572319>Question 572319</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This solve by substitution method is really confusing me I really need help with this please\r<BR>\n" );
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document.write( "2x+2y=2<BR>\n" );
document.write( "-8x+y=28 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368364 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368364\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=8x+28<BR>\n" );
document.write( "2x+2y=2<BR>\n" );
document.write( "2x+2(8x+28)=2<BR>\n" );
document.write( "2x+16x+56=2<BR>\n" );
document.write( "18x=-54<BR>\n" );
document.write( "x=-54/18<BR>\n" );
document.write( "x=-3<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "2*-3+2y=2<BR>\n" );
document.write( "-6+2y=2<BR>\n" );
document.write( "2y=8<BR>\n" );
document.write( "y=8/2<BR>\n" );
document.write( "y=4<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "-8(-3)+4=28<BR>\n" );
document.write( "24+4=28<BR>\n" );
document.write( "I hope that helps.<BR>\n" );
document.write( "Bob </SPAN>\n" );
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