document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=572263>Question 572263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you visualy show me step by step how to find the vertex of the equation y=5(x+5)(x-2)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368356 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = 5(x+5)(x-2)\r<BR>\n" );
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document.write( "y = 5(x^2 + 3x - 10)\r<BR>\n" );
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document.write( "y = 5x^2 + 15x - 50\r<BR>\n" );
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document.write( "The vertex we need is in the form (x,y).\r<BR>\n" );
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document.write( "To find the x-coordinate, use x = -b/2a.\r<BR>\n" );
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document.write( "a = 5 and b = 15\r<BR>\n" );
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document.write( "x = -15/2(5)\r<BR>\n" );
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document.write( "x = -15/10\r<BR>\n" );
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document.write( "x = -3/2\r<BR>\n" );
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document.write( "To find y, replace x in the above equation with -3/2 and simplify.\r<BR>\n" );
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document.write( "y = 5(-3/2)^2 + 15(-3/2) - 50\r<BR>\n" );
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document.write( "y =  -245/4\r<BR>\n" );
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document.write( "The vertex is the pont (-3/2, -245/4).\r<BR>\n" );
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