document.write( "Question 571889: A set of data is normally distributed with a mean of 100 and standard deviation of 15.
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document.write( "· What would be the standard score for a score of 85?
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document.write( "· What percentage of scores is between 100 and 85?
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document.write( "· What would be the percentile rank for a score of 85?\r
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document.write( "I am lost and my teacher will not respond to me via email or anything. PLEASE HELP!!! \n" );
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Algebra.Com's Answer #368264 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A set of data is normally distributed with a mean of 100 and standard deviation of 15. \n" ); document.write( "· What would be the standard score for a score of 85? \n" ); document.write( "z(85) = (85-100)/15 = -15/15 = -1 \n" ); document.write( "That means 85 is one standard deviation to the left of the mean. \n" ); document.write( "------ \n" ); document.write( "· What percentage of scores is between 100 and 85? \n" ); document.write( "One standard deviation from the mean covers 34% of the population. \n" ); document.write( "normalcdf(85,100,100,15) = 0.3413 \n" ); document.write( "---------------------------------------- \n" ); document.write( "· What would be the percentile rank for a score of 85? \n" ); document.write( "The tail to the left of 85 must have 0.5000-0.3413 = 0.1587 of the population. \n" ); document.write( "The percentile score must be 15.87%ile \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " \n" ); document.write( " |