document.write( "Question 571956: Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 40 pages per hour. If Tom starts reading a novel at 4:30 and Jan begins reading an identical copy of the same book at 5:20, at what time will they be reading the same page? \n" ); document.write( "
Algebra.Com's Answer #368254 by lwsshak3(11628)\"\" \"About 
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Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 40 pages per hour. If Tom starts reading a novel at 4:30 and Jan begins reading an identical copy of the same book at 5:20, at what time will they be reading the same page?
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\n" ); document.write( "30 pages/hr=30/60 pages/min=1/2 pages/min
\n" ); document.write( "40 pages/hr=40/60 pages/min=2/3 pages/min
\n" ); document.write( "5:20-4:30=50 min
\n" ); document.write( "..
\n" ); document.write( "let x=minutes Tom was reading novel
\n" ); document.write( "x-50=minutes Jan was reading novel
\n" ); document.write( "..
\n" ); document.write( "pages tom read=x*1/2=x/2
\n" ); document.write( "pages Jan read=2/3*(x-50)
\n" ); document.write( "x/2=2/3*(x-50)=(2x-100)/3
\n" ); document.write( "LCD=6
\n" ); document.write( "3x=2(2x-100)=4x-200
\n" ); document.write( "x=200 min=3hrs+20 min
\n" ); document.write( "ans:
\n" ); document.write( "Time Tom and Jan will be reading from the same page=4:30+3hrs+10 min=7:40\r
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