document.write( "Question 571908: I am ridiculously confused on these problems. I don't even know where to start with them. \r
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document.write( "x²+41 =8x and the answer has to be in the form of a+bi\r
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document.write( "The second one is:
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document.write( "x²+13/2x=3 \r
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document.write( "and then the last one is:
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document.write( "The width of a rectangle is 1 ft less than the length. The area is 2ft²
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document.write( "width=
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document.write( "length= \n" );
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Algebra.Com's Answer #368225 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! x²+41 =8x and the answer has to be in the form of a+bi \n" ); document.write( "--- \n" ); document.write( "x^2 -8x + 41 = 0 \n" ); document.write( "x = [8 +- sqrt(64-4*41)]/2 \n" ); document.write( "x = [8 +- sqrt(-100)]/2 \n" ); document.write( "--- \n" ); document.write( "x = 4 +- 5i \n" ); document.write( "========================= \n" ); document.write( " \n" ); document.write( "The second one is: \n" ); document.write( "x²+13/2x=3 \n" ); document.write( "x^2 + 13 -6x = 0 \n" ); document.write( "x^2 -6x + 13 = 0 \n" ); document.write( "x = [6 +- sqrt(36-4*13)]/2 \n" ); document.write( "x = [6 +- sqrt(-16)]/2 \n" ); document.write( "x = 3 +- 2i \n" ); document.write( "========================= \n" ); document.write( "and then the last one is: \n" ); document.write( "The width of a rectangle is 1 ft less than the length. The area is 2ft² \n" ); document.write( "Let length be \"x\" ; then width x-1 \n" ); document.write( "Equation: \n" ); document.write( "x(x-1) = 2 \n" ); document.write( "x^2-x-2 = 0 \n" ); document.write( "Positive solution: \n" ); document.write( "(x-2)(x+1) = 0 \n" ); document.write( "x = 2 (length) \n" ); document.write( "x-1 = 1 (width) \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "====================== \n" ); document.write( " |