document.write( "Question 571905: In the lab, Ivan has two solutions that contain alcohol and is mixing them with each other. He uses 300 milliliters less of Solution A than Solution B. Solution A is 11% alcohol and Solution B is 16% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 291 milliliters of pure alcohol?\r
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Algebra.Com's Answer #368223 by stanbon(75887)\"\" \"About 
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He uses 300 milliliters less of Solution A than Solution B. Solution A is 11% alcohol and Solution B is 16% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 291 milliliters of pure alcohol?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "A = B-300 ml
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\n" ); document.write( "0.11A + 0.16B = 291
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\n" ); document.write( "0.11(B-300) + 0.16B = 291
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "11B - 3300 + 16B = 29100
\n" ); document.write( "27B = 32400
\n" ); document.write( "B = 1200 ml (amt. of solution B needed)
\n" ); document.write( "A = B-300 = 900 ml (amt. of solution A needed
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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