document.write( "Question 571905: In the lab, Ivan has two solutions that contain alcohol and is mixing them with each other. He uses 300 milliliters less of Solution A than Solution B. Solution A is 11% alcohol and Solution B is 16% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 291 milliliters of pure alcohol?\r
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Algebra.Com's Answer #368223 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! He uses 300 milliliters less of Solution A than Solution B. Solution A is 11% alcohol and Solution B is 16% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 291 milliliters of pure alcohol? \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "A = B-300 ml \n" ); document.write( "--- \n" ); document.write( "0.11A + 0.16B = 291 \n" ); document.write( "--- \n" ); document.write( "0.11(B-300) + 0.16B = 291 \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "11B - 3300 + 16B = 29100 \n" ); document.write( "27B = 32400 \n" ); document.write( "B = 1200 ml (amt. of solution B needed) \n" ); document.write( "A = B-300 = 900 ml (amt. of solution A needed \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " |