document.write( "Question 571847: In a rectangle, the length is fifthteen less than three times the width. If the perimeter is 34, what is the length? \n" ); document.write( "

Algebra.Com's Answer #368205 by mananth(16946) $\"\"$ $\"About$

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\n" ); document.write( "Perimeter = 34 feet
\n" ); document.write( "Length 1 ( 3 x -15 )
\n" ); document.write( "Width = 1 x ft
\n" ); document.write( "Perimeter =2(L+W)
\n" ); document.write( "Perimeter = 2((3x-15)+x)
\n" ); document.write( "Perimeter = 2((3x-15+x)
\n" ); document.write( "Perimeter = 2(6x-15+2x)
\n" ); document.write( "34=16x-30
\n" ); document.write( "34-=16x
\n" ); document.write( "34+30=8x
\n" ); document.write( "64=8x
\n" ); document.write( "x=8ft Width
\n" ); document.write( "plug x in the expression for length(3x-15)
\n" ); document.write( " we get( 24-15)
\n" ); document.write( " Length= =9 feet
\n" ); document.write( "
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