document.write( "Question 571712: if Area=5000
\n" ); document.write( " Length= 30+Width
\n" ); document.write( " then what is Width
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Algebra.Com's Answer #368185 by KMST(5347)\"\" \"About 
You can put this solution on YOUR website!
So as not to repeat the whole words \"length\" and \"width\" too many times, we abbreviate by saying
\n" ); document.write( "Let L be the length, and let W be the width.
\n" ); document.write( "\"L=W%2B30\"
\n" ); document.write( "\"Area=L%2AW\" --> \"Area=%28W%2B30%29W\"
\n" ); document.write( "We get the equation
\n" ); document.write( "\"%28W%2B30%29W=5000\" --> \"W%5E2%2B30W=5000\" --> \"W%5E2%2B30W-5000=0\"
\n" ); document.write( "We can find the solutions to that equation, applying the quadratic formula, as
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\n" ); document.write( "We need to discard the negative solution, because the width is a positive number, and we are left with \"highlight%28W=-15+%2B+5sqrt%28209%29%29\"
\n" ); document.write( "\"L=-15+%2B+5sqrt%28209%29%2B30\" --> \"highlight%28L=15+%2B+5sqrt%28209%29%29\"
\n" ); document.write( "Those values are not pretty, but are exact solutions. They cannot be written as exact decimals, but W = approximately 57.284 and L = approximately 87.284
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