document.write( "Question 571707: Please help! I really need to learn how to do travel word problems and they confuse me so much. \r
\n" ); document.write( "\n" ); document.write( "The speed of a river's current is 4 miles per hour. You travel 2 miles with the current and then return to where you started in a total time of 1.25 hours. What is your speed in the still water in miles per hour?
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Algebra.Com's Answer #368181 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The speed of a river's current is 4 miles per hour.
\n" ); document.write( " You travel 2 miles with the current and then return to where you started in a total time of 1.25 hours.
\n" ); document.write( " What is your speed in the still water in miles per hour?
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\n" ); document.write( "let s = the speed of your boat in still water
\n" ); document.write( "then
\n" ); document.write( "(s-4) = your effective speed up-stream
\n" ); document.write( "and
\n" ); document.write( "(s+4) = your effective speed down-stream
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
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\n" ); document.write( "Time upstr + time downstr = 1.25 hrs
\n" ); document.write( "\"2%2F%28%28s-4%29%29\" + \"2%2F%28%28s%2B4%29%29\" = 1.25
\n" ); document.write( "Multiply by (s-4)(s+4)
\n" ); document.write( "(s+4)*s-4)\"2%2F%28%28s-4%29%29\" + (s+4)(s-4*\"2%2F%28%28s%2B4%29%29\" = 1.25(s+4)(s-4)
\n" ); document.write( "Cancel the denominators, and you have
\n" ); document.write( "2(s+4) + 2(s-4) = 1.25(s^2-16)
\n" ); document.write( ":
\n" ); document.write( "2s + 8 + 2s - 8 = 1.25s^2 - 20
\n" ); document.write( "Combine to form a quadratic equation
\n" ); document.write( "0 = 1.25s^2 - 4s - 20
\n" ); document.write( "You have to use the quadratic equation to find s
\n" ); document.write( "only on solution will make sense, I got
\n" ); document.write( "5.91 mph is his approx speed in still water
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