document.write( "Question 571707: Please help! I really need to learn how to do travel word problems and they confuse me so much. \r
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document.write( "The speed of a river's current is 4 miles per hour. You travel 2 miles with the current and then return to where you started in a total time of 1.25 hours. What is your speed in the still water in miles per hour? \n" );
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Algebra.Com's Answer #368181 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! The speed of a river's current is 4 miles per hour. \n" ); document.write( " You travel 2 miles with the current and then return to where you started in a total time of 1.25 hours. \n" ); document.write( " What is your speed in the still water in miles per hour? \n" ); document.write( ": \n" ); document.write( "let s = the speed of your boat in still water \n" ); document.write( "then \n" ); document.write( "(s-4) = your effective speed up-stream \n" ); document.write( "and \n" ); document.write( "(s+4) = your effective speed down-stream \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "Time upstr + time downstr = 1.25 hrs \n" ); document.write( " \n" ); document.write( "Multiply by (s-4)(s+4) \n" ); document.write( "(s+4)*s-4) \n" ); document.write( "Cancel the denominators, and you have \n" ); document.write( "2(s+4) + 2(s-4) = 1.25(s^2-16) \n" ); document.write( ": \n" ); document.write( "2s + 8 + 2s - 8 = 1.25s^2 - 20 \n" ); document.write( "Combine to form a quadratic equation \n" ); document.write( "0 = 1.25s^2 - 4s - 20 \n" ); document.write( "You have to use the quadratic equation to find s \n" ); document.write( "only on solution will make sense, I got \n" ); document.write( "5.91 mph is his approx speed in still water \n" ); document.write( " |