document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54559>Question 54559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 3 more than half of a second number. If the average of the two numbers is 15 1/2, find the smaller of the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36817 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (X+Y)/2=15.5 THEN X+Y=31 OR X=31-Y AND X=3+Y/2 THUS 31-Y=3+Y/2 OR Y+Y/2=31-3 OR\r<BR>\n" );
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document.write( "3/2Y=28 OR 3Y=28*2 OR 3Y=56 OR Y=18 2/3 THEN X=31-18/2/3 OR X=12 1/3 [THE SMALLER NUMBER]\r<BR>\n" );
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document.write( "PROOF 18 2/3+12 1/3=31 OR 31=31 AND 12 1/3=3+(18 2/3)/2 OR 12 1/3=3+9 1/3 OR\r<BR>\n" );
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document.write( "12 1/3=12 1/3 </SPAN>\n" );
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