document.write( "Question 571472: A swimming pool can be filled up by pipes A and B in 3 hours and 35 minuted. If pipe A can fill the pool in 6 1/2 hours, how long can pipe B fill it alone? \n" ); document.write( "
Algebra.Com's Answer #368126 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A swimming pool can be filled up by pipes A and B in 3 hours and 35 minutes.
\n" ); document.write( " If pipe A can fill the pool in 6 1/2 hours, how long can pipe B fill it alone?
\n" ); document.write( ":
\n" ); document.write( "We can do this in minutes, avoid those annoying fractions, then convert the answer back to hrs and min.
\n" ); document.write( "3(60) + 35 = 215 min
\n" ); document.write( "6(60) + 30 = 390 min
\n" ); document.write( ":
\n" ); document.write( "Let B = time for pipe B to fill it alone
\n" ); document.write( "Let the completed job = 1; (a full pool)
\n" ); document.write( ":
\n" ); document.write( "A typical shared work equation
\n" ); document.write( "\"215%2F390\" + \"215%2FB\" = 1
\n" ); document.write( "multiply by 390B
\n" ); document.write( "390B*\"215%2F390\" + 390B*\"215%2FB\" = 390B
\n" ); document.write( "cancel the denominators and you have
\n" ); document.write( "215B + 390(215) = 390B
\n" ); document.write( "83850 = 390B - 215B
\n" ); document.write( "83850 = 175B
\n" ); document.write( "B = \"83850%2F175\"
\n" ); document.write( "B = 479.143 minutes
\n" ); document.write( ":
\n" ); document.write( "Convert to hrs and min, divide by 60; mult the decimal portion times 60
\n" ); document.write( "7 + .986(60) = 7 hrs 59 minutes for B to the job
\n" ); document.write( "
\n" ); document.write( "
\n" );