document.write( "Question 571552: a plus 1 over 4 minus a over 6 \n" ); document.write( "
Algebra.Com's Answer #368121 by Edwin McCravy(20060)\"\" \"About 
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document.write( "a + \"1%2F4\" - \"a%2F6\"\r\n" );
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document.write( "Write a as \"a%2F1\"\r\n" );
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document.write( "\"a%2F1\" + \"1%2F4\" - \"a%2F6\"\r\n" );
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document.write( "The LCD is 12.\r\n" );
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document.write( "The denominator of \"a%2F1\" needs to be multiplied by 12 to become\r\n" );
document.write( "the LCD of 12, so multiply the first fraction by \"red%28%2812%29%2F%2812%29%29\"\r\n" );
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document.write( "\"a%2F1\"\"red%28%2812%29%2F%2812%29%29\" + \"1%2F4\" - \"a%2F6\"\r\n" );
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document.write( "The denominator of \"1%2F4\" needs to be multiplied by 3 to become\r\n" );
document.write( "the LCD of 12, so multiply the second fraction by \"red%28%283%29%2F%283%29%29\"\r\n" );
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document.write( "\"a%2F1\"\"red%2812%2F12%29\" + \"1%2F4\"\"red%28%283%29%2F%283%29%29\" - \"a%2F6\"\r\n" );
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document.write( "The denominator of \"a%2F6\" needs to be multiplied by 2 to become\r\n" );
document.write( "the LCD of 12, so multiply the third fraction by \"red%28%282%29%2F%282%29%29\"\r\n" );
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document.write( "\"a%2F1\"\"red%28%2812%29%2F%2812%29%29\" + \"1%2F4\"\"red%28%283%29%2F%283%29%29\" - \"a%2F6\"\"red%28%282%29%2F%282%29%29\"\r\n" );
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document.write( "Multiply the numerators and the denominators in each of the the three\r\n" );
document.write( "terms:\r\n" );
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document.write( "\"%2812a%29%2F12\" + \"3%2F12\" - \"2a%2F12\"\r\n" );
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document.write( "Now that all three fractions have the same denominator, we combine\r\n" );
document.write( "the three numerators and write that over the LCD of 12:\r\n" );
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document.write( "\"%2812a%2B3-2a%29%2F12\"\r\n" );
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document.write( "Combine the like terms 12a and -2a and get 10a.\r\n" );
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document.write( "So the final simplification is\r\n" );
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document.write( "\"%2810a%2B3%29%2F12\"\r\n" );
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document.write( "Edwin

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