document.write( "Question 571547: it takes bob the boy scout 10 hours to paddle upstream against the current a distance of 15 miles. when he turn around he finds it only takes him 5 hours to 'paddle 22.5 miles with current. how fast is bob's boat going in still water and what is the speed of the current of the river? \n" ); document.write( "
Algebra.Com's Answer #368113 by stanbon(75887)\"\" \"About 
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it takes bob the boy scout 10 hours to paddle upstream against the current a distance of 15 miles. when he turn around he finds it only takes him 5 hours to 'paddle 22.5 miles with current. how fast is bob's boat going in still water and what is the speed of the current of the river?
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\n" ); document.write( "Upstream DATA:
\n" ); document.write( "time = 10 hrs ; distance = 15 miles ; rate = d/t = 15/10 = 1.5 mph
\n" ); document.write( "----------------
\n" ); document.write( "Downstream DATA:
\n" ); document.write( "time = 5 hrs ; distance = 22 miles ; rate = d/t = 22/5 = 4.4 mph
\n" ); document.write( "---------------
\n" ); document.write( "Equations:
\n" ); document.write( "upstream: b-c = 1.5 mph
\n" ); document.write( "downstream: b+c = 4.4 mph
\n" ); document.write( "-------------------------------
\n" ); document.write( "Add and solve for \"b\":
\n" ); document.write( "2b = 5.9 mph
\n" ); document.write( "b = 2.95 (speed of the boat in still water)
\n" ); document.write( "---
\n" ); document.write( "Solve for \"c\":
\n" ); document.write( "b + c = 4.4
\n" ); document.write( "2.95 + c = 4.4
\n" ); document.write( "c = 1.45 mph (speed of the current)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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