document.write( "Question 571510: hey, would you please be able to help me with the following question
\n" ); document.write( "a student runs three times as fast as she walks. she walked for 3 hours and ran for 2 hours and altogether went 36km. what was her speed of walking
\n" ); document.write( "thanks \n" ); document.write( "

Algebra.Com's Answer #368091 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+s+\"$ = her speed walking in km/hr
\n" ); document.write( " $\"+3s+\"$ = her speed running in km/hr
\n" ); document.write( "Let $\"+d+\"$ = distance traveled walking in km
\n" ); document.write( " $\"+36+-+d+\"$ = distance traveled running in km
\n" ); document.write( "-----------------
\n" ); document.write( "Her equation walking:
\n" ); document.write( "(1) $\"+d+=+s%2A3+\"$
\n" ); document.write( "Her equation running:
\n" ); document.write( "(2) $\"+36+-+d+=+3s%2A2+\"$
\n" ); document.write( "--------------------
\n" ); document.write( "(2) $\"+36+-+d+=+6s+\"$
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"36+-+3s+=+6s+\"$
\n" ); document.write( "(2) $\"+9s+=+36+\"$
\n" ); document.write( "(2) $\"+s+=+4+\"$
\n" ); document.write( "Her speed walking was 4 km/hr
\n" ); document.write( "check answer:
\n" ); document.write( "(1) $\"+d+=+s%2A3+\"$
\n" ); document.write( "(1) $\"+d+=+4%2A3+\"$
\n" ); document.write( "(1) $\"+d+=+12+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+36+-+d+=+3%2A4%2A2+\"$
\n" ); document.write( "(2) $\"+36+-+d+=+24+\"$
\n" ); document.write( "(2) $\"+d+=+12+\"$
\n" ); document.write( "OK \n" ); document.write( "

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