document.write( "Question 570367: log[6](x+1)+log[6](x)=1 \n" ); document.write( "
Algebra.Com's Answer #368081 by lwsshak3(11628)\"\" \"About 
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Solve for x
\n" ); document.write( "log[6](x+1)+log[6](x)=1
\n" ); document.write( "log6[x(x+1)]=1
\n" ); document.write( "convert to exponential form: base(6) raised to log of the number(1)=number[x(x+1)]
\n" ); document.write( "6^1=[x(x+1)]
\n" ); document.write( "6=x^2+x
\n" ); document.write( "x^2+x-6=0
\n" ); document.write( "(x+3)(x-2)=0
\n" ); document.write( "x=-3(reject, (x+1)>0)
\n" ); document.write( "or
\n" ); document.write( "x=2
\n" ); document.write( "
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