document.write( "Question 571198: Monica has three times as many nickels as pennies and twice as many quarters as nickels. In all she has $3.25. How many coins of each type does she have? \n" ); document.write( "

Algebra.Com's Answer #368065 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Let n = no. of nickels
\n" ); document.write( "Let p = no. of pennies
\n" ); document.write( "Let q = no. of quarters
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\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"Monica has three times as many nickels as pennies\"
\n" ); document.write( "n = 3p
\n" ); document.write( "or divide both sides by 3
\n" ); document.write( "p = $\"1%2F3\"$ n
\n" ); document.write( ":
\n" ); document.write( "\" and twice as many quarters as nickels.\"
\n" ); document.write( "q = 2n
\n" ); document.write( ":
\n" ); document.write( "\"In all she has $3.25.\"
\n" ); document.write( ".01p + .05n + .25q = 3.25
\n" ); document.write( "Replace p and q from the 1st two equations
\n" ); document.write( ".01 $\"1%2F3\"$ n + .05n + .25(2n) = 3.25
\n" ); document.write( " $\".01%2F3\"$ n + .05n + .50n = 3.25
\n" ); document.write( "Multiply by 3 to get rid of the denominators, results:
\n" ); document.write( ".01n + .15n + 1.5n = 9.75
\n" ); document.write( "1.66n = 9.75
\n" ); document.write( "n = 5.87, solution has to be an integer, so there something wrong with this problem, a fatal error as they say\r
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