document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=571344>Question 571344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let x = log 2, y = log 3, and z = log 10.<BR>\n" );
document.write( "Express the logarithm in terms of x, y, and z.<BR>\n" );
document.write( "How do i solve it when the question is log 1.5 or log 0.75?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #368052 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=368052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = log 2, y = log 3, and z = log 10.<BR>\n" );
document.write( "Express the logarithm in terms of x, y, and z.<BR>\n" );
document.write( "How do i solve it when the question is log 1.5 or log 0.75?<BR>\n" );
document.write( "**<BR>\n" );
document.write( "log(1.5)=log(3/2)=log(3)-log(2)=y-x<BR>\n" );
document.write( "log (.75)=log(3/4)=log(3)-log(4)=log(3)-log(2^2)=log(3)-2log(2)=y-2x </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );