document.write( "Question 571243: By weight one alloy has 40% Aluminum, 38% Copper and the rest Cadmium. The second alloy has 52%, 20% and 28% Aluminum, Copper, and Cadmium respectively. The Aluminum, Copper, and Cadmium content of the third alloy is 61%, 12% and 27% respectively. How much of each alloy must be mixed to produce 1000 Lbs of alloy with the following content of 50.2% Aluminum, 23.8% Copper and 26% Cadmium? I am completely stumped on how to figure this one out. Can someone help Please? \n" ); document.write( "

Algebra.Com's Answer #368040 by scott8148(6628) $\"\"$ $\"About$

You can put this solution on YOUR website!
let x = amount of 1st alloy , y = amount of 2nd alloy , and z = amount of 3rd alloy\r
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\n" ); document.write( "\n" ); document.write( "you are given the amounts of the components in the final alloy
\n" ); document.write( "___ Al = (50.2%)(1000) = 502 lb
\n" ); document.write( "___ Cu = (23.8%)(1000) = 238 lb
\n" ); document.write( "___ Cd = (26%)(1000) = 260 lb\r
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\n" ); document.write( "\n" ); document.write( ".4x + .52y + .61z = 502\r
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\n" ); document.write( "\n" ); document.write( ".38x + .2y + .12z = 238\r
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\n" ); document.write( "\n" ); document.write( ".22x + .28y + .27z = 260\r
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\n" ); document.write( "\n" ); document.write( "solve the system of equations to find the amounts of the three alloys\r
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\n" ); document.write( "\n" ); document.write( "you might want to think about Cramer's Rule \n" ); document.write( "

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